10 points plus brainliest!

what is the equation of the line that passes through (–2, –3) and is perpendicular to 2x – 3y = 6?

a.
y=-3/2x-6
b.
y=-2/3x+6
c.
y=2x+3
d.
y=3/2x

Start by finding the slope.

2x – 3y = 6
-3y = -2x + 6
y = 2/3x - 2
So the slope of this line is 2/3. The slope perpendicular to this is -3/2.

Now find 'b'.

y = -3/2x + b
-3 = -3/2(-2) + b
-3 = 6/2 + b
-3 = 3 + b
-6 = b

So your answer is 
y = -3/2x - 6 or A..

I hope this helps! :D Feel free to ask any questions.And please, only if you think I deserve it, it would help a bunch if you marked this answer as branliest!

[[ Also, quick testing tip. At the point where you found what the perpendicular slope was, you didn't have to do the rest of the problem, because -3/2 is the only slope on answer A. ]]

Sin(a)+cos(a)+cot(a)-1=2(csc(x)+1)