Find the solutions to the equation sin2x=square root of 3 cos2x

Sin2x=square root(3)*cos2x
sin(2x)/cos(2x)=square root of 3
tan(2x)=square root of 3

tan(x)=square root of 3 when y=pi/3+pi*n
tan(2x)=square root of 3 when y=pi/6+pi*n

{x:x=pi/3+pi*n, where n is an element of the integers}