Which is the equation of a parabola with vertex (0, 0), that opens to the left and has a focal width of 12?

Step-by-step explanation:

We need to find the equation of parabola using given information

If parabola open left and passes through origin then equation is

Focal width = 12

Focal width passes through focus and focus is mid point of focal width.

Focus of above parabola would be (-a,0)

Passing point on parabola (-a,6) and (-a,-6)

Now we put passing point into equation and solve for a

a can't be negative.

Therefore, a=3

Focus: (-3,0)

Equation of parabola:

Please see the attachment of parabola.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

$119.20

step-by-step explanation:

$372.50 - 60% off is $149. $149-20% off is $119.20