If f(–2) = 0, what are all the factors of the function ? use the remainder theorem

The function is: f ( x ) = x³ - 2 x² - 68 x - 120
If f ( - 2 ) = 0, we have to divide this equation by: ( x + 2 )
( x³ - 2 x² - 68 x - 120 ) : ( x + 2 ) = x² - 4 x - 60
- x³ - 2 x²

       - 4 x² - 68 x - 120
         4 x² + 8 x
 
                - 60 x - 120
                  60 x + 120
               
                               0
After that for a function: f ( x ) = x² - 4 x - 60;   f (  - 6 ) = 0
( x² - 4 x - 60 ) : ( x + 6 ) = x - 10
 -x² - 6 x

        - 10 x - 60
          10 x + 60
         
                      0

       C )    ( x - 10 ) ( x + 2 ) ( x + 6 )
 

The answer would be -3.9> -4.5

It's like discovering the answer to a puzzle. the purpose in solving an equation is to find the value or values of the variable that makes it a true statement. any value of the variable that makes the equation true is called a solution to the equation.