Eli has 7 black pens and 5 blue pens in his desk drawer. he also has 3 yellow highlighters, 2 green highlighters, and 5 pink highlighters in his pencil case. if he chooses one pen and one highlighter without looking, what is the probability that he will get a black pen and he will not get a green highlighter?

The probability is 7/15.

Step-by-step explanation:

Total number of pens = 7+5 = 12

Out of 12, 7 are black and 5 are blue pens.

Similarly, total number of highlighters = 3+2+5 = 10

Out of 10, 3 are yellow highlighters, 2 are green highlighters, and 5 are pink .

Now, Eli is choosing one pen and one highlighter without looking, so the probability that he will get a black pen and he will not get a green highlighter will be =

=

Hence, the probability is 7/15 or 46.66%.

70,000 + 6,000 + 800 + 30

step-by-step explanation:

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

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