You are given the steps for using a compass and a straightedge to construct a perpendicular to a given line through a point not lying on the given line. arrange the steps in the proper sequence
geometry

Place compass needle  on external point R

Make compass width greater than distance from R to given line

Draw arc cutting given at 2 points

Mark / label points of intersection P and Q

Don't change compass width, move compass needle to Q, draw another arc below line crossing previous arc

Move compass needle to P , make arc below line

Mark / label point of intersection S.

Draw line from external point R to point where arcs intersect, S

Line RS is perpendicular to line PQ and passes thru external point R

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3