The point slope form of the equation of the line passes through (-9,-2) and (1,3) is y-3=1/2 (x-1)

y - 3 = (1/2)(x - 1)

Step-by-step explanation:

As we move from the point (-9,-2) to the point (1,3), x increases by 10 and y increases by 5.  Thus, the slope of this line is m = rise / run = 5/10, or 1/2.

Using info from the 2nd point (1, 3), the equation of this line in point-slope form is

y - 3 = (1/2)(x - 1)

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west