Abasketball team plays 3 games in a holiday tournament. according to the tree diagram, how many outcomes are possible?
a. 5
b. 6
c. 7
d. 8

Hence, the possible number of outcomes are:

Option: d ( d. 8)

Step-by-step explanation:

It is given that:

A basketball team plays 3 games in a holiday tournament.

(   We know that:

Tree diagrams display all the possible outcomes of an event. Each branch in a tree diagram represents a possible outcome )

The possible number of outcomes that are possible are:

8.

Let the team be denoted by 'A'

so, the outcome of the game may be winning(W) or losing(L) the game.

Option d. 8 is the correct option.

Step-by-step explanation:

A basketball team plays 3 games in a holiday tournament.

Let the chance of winning of the team be represented as W and losing by L

As per tree diagram attached we can see

In the first game

Number possibilities will be 2 either win or lose

After second games

Number of possibilities will be 4 [(L L), (L W), (W L), (W W)]

After third game

Number of possibilities will be 8 [ (L L), (L W), (W L), (W W), (L L), (L W), (W L),  (W W)]

So total outcomes which are possible are 8.

Option d. 8 is the correct option.

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation:

3.how is solving radical equations different than solving linear equations?

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