Mathematics, 27.09.2019 01:30 wbrandi118
The area of the ice surface of a skating rink is about 221 yd2. the rink is about the shape of a rectangle where the ice-surface width is 4 yd longer than its length. find the dimensions of the surface. a. length = 13 yd, width = 17 yd b. length = 21 yd, width = 17 yd c. length = 17 yd, width = 21 yd d. length = 17 yd, width = 13 yd
Answers: 1
The area of the ice surface of a skating rink is about 221 yd2. the rink is about the shape of a rec...
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