During the first 60 seconds of a rocket launch, the momentum of the rocket increased by 200,000 kgm/s. what was the impulse applied to the rocket during this time?
a. 120,000,000 kgm/s
b. 33,333 kgm/s
c. 500,000 kgm/s
d. 200,000 kgm/s

impulse, J = 200,000 kg-m/s

Step-by-step explanation:

It is given that,

The momentum of the rocket is increased by 200,000 kg-m/s during the first 60 seconds. The impulse applied to the rocket during this time is given by the change in momentum i.e.

Another definition of impulse is given by the force applied and the small interval of time i.e.

So, in this case impulse applied to the rocket during 60 seconds is equivalent to the change in momentum i.e. 200,000 kg-m/s. Hence, the correct option is (d).

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation:

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.