What are the excluded values of the function y=3/4x+64

a. x= 0
b. x= -64
c. x= -16
d. x= -8

Option C is correct.

Step-by-step explanation:

Given Function is

We have to find values which is excluded from the function.

We know that Values are excluded where function doesn't exist.

Given function is rational function.

So, Values excluded where denominator equals to 0.

⇒ 4x + 64 = 0

4x = -64

x = -16

Therefore, Option C is correct.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

step-by-step explanation:

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