Janelle made ordered lists of the heights, in inches, of the students in ms. carver’s and mr. wright’s homerooms. she found the two lists had the same median value, but the list from ms. carver’s class showed greater variability. if the shortest student in mr. wright’s homeroom is 48 inches tall and the tallest student is 64 inches tall, what could be the heights of the shortest and tallest students in ms. carver’s homeroom?

Answer with explanation:

Given information is :

There are 2 homerooms namely Mr. Wright's and Ms. Carver. The shortest student in Mr. Wright’s homeroom is 48 inches tall and the tallest student is 64 inches tall.  

Janelle found that two lists had the same median value, but the list from Ms. Carver’s class showed greater variability. This means, the difference between the heights of shortest to tallest students will be more in Ms. Carver's homeroom than Mr. Wright's.

Now, the difference in Mr. Wright's homeroom is = 64-48=16

So, the heights in Ms. Carver's homeroom will be more than 64 and less than 48.

Like - 66-46 = 20 ; 68-44 = 24 etc.

Note: If it is a multiple choice question, you can select the answer with the highest difference.

B 47 inches and 66 inches

Step-by-step explanation:

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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step-by-step explanation:

ever thing time 1 is a multiply by 1 it get