Find the x-intercepts of the parabola with vertex (-1,-16) and y intercept (0,15), write your answer in this form (x1,,y2)

hello :
the parabola's equation is : f(x) = a(x+1)²+16
the coefficient of the squared expression in the parabola's equation is : a
but ; f(0) = 15 ...  ( y-intercepts (0,15) )

15 = a(0+1)²+16
15 =a +16

a=-1
f(x) = -(x-1)²+16

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

d

step-by-step explanation: