Anumber cube is rolled 360 times and the results are recorded as follows: 41 ones, 54 twos, 62 threes, 75 fours, 33 fives, and 95 sixes. what is the experimental probability of rolling a two or a three?

P(3's) =62/360 = 31/180 = 0.17

P(2's) = 54/360 = 3/20 =0.15

P93's) or P(2's) = 0.17 + 0.15 = 0.32 or 32%

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.