B. use de moivre's theorem to compute the following: b. ^3√(8cos(4π / 5) + 8isin(4π / this is the only one i need with, , i'm so !

De Moivre's Theorem states that if a complex number is written in the polar coordinate form [ r (cosθ + sinθ)] and you raise it to the power n, then this can be evaluated by raising the modulus (r) to the power and multiply the argument (θ) by the power.  This therefore would give r ⁿ  [cos (nθ) + sin (nθ)].

let A =  ∛ (8 cos (4π / 5) + 8 i sin (4π / 5))

⇒  A = ∛ (8 [cos (4π / 5) + i sin (4π / 5)])

Now by applying De Moivre's Theorem,

⇒ A = [cos ( × ) + sin ( × )

⇒ A = 2 [ cos () +   sin ()

⇒ A = 2 [0.0117 +   0.01297 ] rads

Ithink the answer is c just trying to others