Triangle pqr has vertices p(–2, 6), q(–8, 4), and r(1, –2). it is translated according to the rule (x, y) → (x – 2, y – 16).

what is the y-value of p'?

the y-value of p' is
.

The y-value of P' is -10.

Step-by-step explanation:

We have been given the vertices of triangle PQR as: P(–2, 6), Q(–8, 4), and R(1, –2). We are asked to find the y-coordinate of point P' after a translation of (x, y) → (x – 2, y – 16).    

We can see that our given translation rule states that we need to translate x-coordinates of triangle PQR to 2 units to right and y-coordinates will be shifted downwards by 16 units.

We can see that y-coordinate of point P' is -10, therefore, the y-value of P' is -10.

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )