Adrawer holds 8 red socks, 13 blue socks, and 15 green socks. what is the probability that a red sock will be drawn first and then a green sock (without replacement?

This is the concept of probability, given that there are 8 red socks, 13 blues socks and 15 green socks, we are required to find that the first socks chosen will a red then a green; Here we shall proceed as follows;
The events are dependent
P(choosing a red socks )=8/36=2/9
P(choosing green socks after red)=15/35=3/7
Thus the probability of choosing  red socks then a green socks without replacement will be:
2/9*3/7
=2/21

2160ft^3 i think you could use a formala to you out with this in the future

No he does not because he can only cover 12 square feet from 15 square feet which he will still need 3 more. this is because if 3×5=15 square feet and 15-12=3 which thats the answer