Mathematics, 24.01.2020 09:31 iheartlink1
How to find the derivative of (3x/sqrt(4x^2+
Answers: 2
![\bf y=\cfrac{3x}{\sqrt{4x^2+1}}\\\\ -----------------------------\\\\ \cfrac{dy}{dx}=\cfrac{3\sqrt{4x^2+1}-3x\left[ \frac{1}{2}(4x^2+1)^{-\frac{1}{2}}\cdot 8x \right]}{(\sqrt{4x^2+1})^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{3\sqrt{4x^2+1}-\left[ \frac{24x^2}{2\sqrt{4x^2+1}} \right]}{(\sqrt{4x^2+1})^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{\frac{(3\sqrt{4x^2+1})(2\sqrt{4x^2+1})-24x^2}{2\sqrt{4x^2+1}}}{(\sqrt{4x^2+1})^2} \\\\\\](/tpl/images/0468/7452/fba3a.png)
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