Asoftware store has put some of its inventory on sale. games are marked down by 15%, and security programs are marked down by 18%. if you pay $35.70 each for two games and $22.96 for a security program, how much have you saved?

the answer is a $17.64

Amount he saved is $17.64.

Step-by-step explanation:

Let the actual price of each game be 'x'.

Let the actual price of security program be 'y'.

Since we have given that

Games are marked down by 15%.

Security programs are marked down by 18%.

Amount paid by him on each game = $35.70

So, Amount paid by him on two games = 35.70 × 2 = $71.4

So, Price of games becomes,

Similarly,

Amount of security program paid by him = $22.96

So, Cost of security program is given by

Hence, Original price of games and security program is $84+$28=$112.

total amount he paid is given by

71.40+22.96=$94.36

So, Amount he saved is given by

Original price - Amount paid

$112-$94.36

=$17.64

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

the answer is d on edge

step-by-step explanation: