Find the factors and zeros of 6x2 + 8x - 28 = 2x2 + 4?
a) 2(x + 4)(x + 2); {-4, -2}
b) 4(x + 4)(x - 2); {-4, 2}
c) 4(x - 4)(x + 2); {4, -2}
d) 4(x - 4)(x - 2); {4, 2}

First solve the equation:

6x^2 + 8x  -28 = 2x^2 + 4

=> 6x^2 - 2x^2 + 8x - 28 - 4 = 0

=> 4x^2  + 8x - 32 = 0

Extract common factor 4:

=> 4[x^2 + 2x - 8] = 0

Now factor the polynomial:

4(x + 4) (x - 2) = 0

=> the solutions are x + 4 = 0 => x = -4, and x - 2 = 0 => x = 2.

So the answer is the option B: 4(x + 4)(x - 2); {-4, 2}