Mathematics, 28.01.2020 08:31 lillianbrowning10
Find all solutions in the interval [0,2pi). sec^2x-2=tan^2x
Answers: 2
![\bf \cfrac{1-2cos^2(x)-sin^2(x)}{cos^2(x)}=0\implies 1-2\underline{cos^2(x)}-sin^2(x) \\\\\\ 1-2\underline{[1-sin^2(x)]}-sin^2(x)=0\implies 1-2+2sin^2(x)-sin^2(x)=0 \\\\\\ -1+sin^2(x)=0\implies sin^2(x)=1\implies sin(x)=\pm\sqrt{1} \\\\\\ sin(x)=\pm 1\implies \measuredangle x=sin^{-1}(\pm1)\implies \measuredangle x= \begin{cases} \frac{\pi }{2}\\\\ \frac{3\pi }{2} \end{cases}](/tpl/images/0476/0485/0c430.png)
Other questions on the subject: Mathematics
Mathematics, 22.06.2019 08:30, Rogeartest4
In 1998 the postal rate to mail the package was 40 cents for the first ounce and 25 cents for each additional ounce or part of an ounce what did it cost to mail a package that weighed 7.7 ounces
Answers: 1
Mathematics, 22.06.2019 08:40, rachanachannagiri
The length pf a rectangle is given by 2t +3 and its height is square root t, where t is time in seconds and the dimensions are in centimeters. find the rate of the change of the area with respect to time. a'(t)=
Answers: 2
You know the right answer?
Find all solutions in the interval [0,2pi). sec^2x-2=tan^2x...
Questions in other subjects:
Mathematics, 13.10.2020 20:01
Geography, 13.10.2020 20:01
Physics, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01
Mathematics, 13.10.2020 20:01
Social Studies, 13.10.2020 20:01
English, 13.10.2020 20:01
