Write an equation in point-slope form of the line through point j(4, 2) with slope 3.

Point slope form is:

y − y = m(x − x)

Where x and y are two known coordinates and m is the slope.

Substitute (4,2) as x and y and 3 as m to find the point-slope form.

y − 2 = 3(x − 4)

Taking it to the next step would be to turn this into slope-intercept form, y=mx+b

y − 2 = 3(x − 4)
y − 2 = 3x − 12
y = 3x − 10

The answer will be y=-5+0 because the slope is -5 and the it has to go through y-axis 0