An acorn falls from the branch of the tree to the ground 25 feet below. the distance, s, that the acorn is from the ground as it falls is represented by the equation s(t)=16ft+25 where t is the number of seconds. for which interval of time is the acron moving through the air?

1.25 seconds

Step-by-step explanation:

Given the function: S(t) = –16*t^2 + 25

where S is the distance from the ground in feet and t is time in seconds.

When the acorn hits the ground its distance is zero, replacing into the equation we get:

0 = –16*t^2 + 25

-25/(-16) = t^2

t = √1.5625

t = 1.25 seconds

homozygous. one is homozygous, while two is heterozygous.

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step-by-step explanation:

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