What is the line of symmetry for the parabola whose equation is y = x2 - 12x + 7?

So the equation of this parabola is a quadratic which means there is a handy formula to find the line of symmetry. The general quadratic form is ax^2 +bx +c, so for our equation:

a=1
b=-12
c=7

The handy formula to find the line of symmetry of a parabola like this is:

x= -b/2a, where x equals the line.

With this we can determine that our line is 12/2 which equals 6.

Our line is at x=6