Need to pass
consider u = {x|x is a negative real number}. which is an empty set?
a {x|x ∈ u and x has a negative cube root}
b {x|x ∈ u and x has a negative square root}
c{x|x ∈ u and x is equal to the product of a positive number and –1}
d {x|x ∈ u and x is equal to the sum of one negative and one positive number}

B={x|x ∈ U and x has a negative square root} is an empty set.

Step-by-step explanation:

let U={x|x is a negative real number}

A= {x|x ∈ U and x has a negative cube root}

It is not an empty set as it contains -1 ∈A such that

∈U . Hence A≠∅

B= {x|x ∈ U and x has a negative square root}

Let there exist some x∈U such that =negative square root of x

but x is a negative real number and its square root must be complex which does not belong to set of real numbers.

for example ,for x=-4∈U

∉set of real numbers.

C={x|x ∈ U and x is equal to the product of a positive number and –1}

C≠∅ as -8∈C such that 8×-1=-8.

D {x|x ∈ U and x is equal to the sum of one negative and one positive number}

D≠∅ as -1∉D such that -1=-5+4.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.