Astudent solves the following equation and determines that the solution is −2. is the student correct? explain. 3 a + 2 − 6a a2 − 4 = 1 a − 2

For this case, we have the following equation (according to the comments):

First, we factor the quadratic expression in the denominator:

Then, we multiply both sides of the equation by (a-2) (a + 2):

Later, canceling similar terms we have:

We do distributive property on the left side of the equation:

By grouping variables and constant terms we have:

Rewriting we have:

Finally, by clearing "a" we have:

Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.

the student correct, but the value of a= -2 is an extraneous solution

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