Arrange the equations in the correct sequence to find the inverse of f(x) =y = 3x/8+x

these must be in correct order!

titles

x(8 + y) = 3y
y=f^-1(x) = (3-x)/8x
8x=3y-xy
8x=y(3-x)
8x=y(x-3)
x= 3y/8+y
y=f^-(x) = 8x/3-x
8x+xy = 3y

You MUST use parentheses around denominator 8+x, or ANY denominator that consist of more than a single number of variable. 

Also, don't use lower case and upper case interchangeably. 
In algebra, x and X are different, as are y and Y. 

f(x) = y = 3x/(8+x) 

Switch x and y, solve for y: 

x = 3y/(8+y) 
x(8+y) = 3y 
8x+xy = 3y 
8x = 3y−xy 
8x = y(3−x) 
y = f⁻¹(x) = 8x/(3−x)

I hope this helps, love