Let f(x)=3 x 2 +2 f(x)=3x2+2
a new quadratic function g(x) is the function f(x) stretched vertically by a factor of 4. what is the equation of g(x)?

F(x)=3x²+2  . The intersection of this parabola with y-axis is 2 [f(0)=2]

If you want to stretch it vertically by a factor of 4. that means instead of 2 previously calculated the total stretch should be 2.4 =8 [f(0)=8]
The stretched equation becomes(x) = 3x² + 8