Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point.

(0, - 3)

interior
exterior
on the circle

The equation of a circle is written as (x-h)^2 + (y-k)^2 = r^2, wherein the center of the circle is at (h,k) and its radius is r. In this case, the circle has the center at (5, -3) with a radius of 5. Thus, the point (0,-3) is on the circle since this point is exactly 5 units to the left of the center of the circle which is equal to the radius of the circle.