How does the mean absolute deviation (mad) of the data in set 1 compare to the mean absolute deviation of the data in set 2?
if necessary, round any values for the mad to the nearest tenth to answer the question.
set 1: 30, 25, 5, 32
set 2: 25, 30, 32
a. the mad of set 1 is 29 more than the mad of set 2.
b. the mad of set 1 is 6.3 more than the mad of set 2.
c. the mad of set 1 is 23 less than the mad of set 2.
d. the mad of set 1 is 6.3 less than the mad of set 2.

Step-by-step explanation:

Given that data set 1 contains the following items

Set 1: 30, 25, 5, 32  

Mean = 92/4 =23

Mean deviation absolute =|X-mean| where x is any item in data set

7,  2, 18, 9

MAD = sum of all mean deviations = 36

and data set 2 the following

Set 2: 25, 30, 32

Mean = 87/3 =29

Mean absolute deviation

= 4, 1,3

MAD of data set 2 = 8

Thus we find that the MAD of set 1 is larger by 28 units.

Option a is the nearest answer.

answer: no, but if it does it's a obvious pattern.

step-by-step explanation:

answer:

step-by-step explanation: