In the triangle shown, xz = 16 and yz = 12. find xy. a) 4 b) 14 c) 18 d) 20

The value of  XY is 20.

Step-by-step explanation:

Given:

XZ = 16

YZ = 12

Since the triangle is not shown:

Assuming it is a right angled triangle with right angle at ∠Z.

We have drawn the triangle for your reference.

Now by Using Pythagoras theorem we get;

Substituting the values we get;

Now taking square root on both side we get;

Hence The value of  XY is 20.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

b i think

step-by-step explanation:

not really sure