The town librarian bought a combination of new-release movies on dvd for $20 and classic movies on dvd for $8. let x represent the number of new releases, and let y represent the number of classics. if the librarian had a budget of $500 and wanted to purchase as many dvds as possible, which values of x and y could represent the number of new-release and classic movies bought? x = 8, y = 45 x = 10, y = 22 x = 16, y = 22 x = 18, y = 18

x = 16, y = 22.

We will solve the problem of linear programming. The case is simple, but we must still be accurate in doing so.

Given:

Question:

Which values of x and y could represent the number of new-release and classic movies bought?

The Process:

Because the number of goods must be positive, then

The total number of DVDs purchased is 20x + 8y (in USD) and must not exceed $500. Thus, we have the inequality

Let's examine one by one for each available option, whether it meets the inequality above.

Option A

This did not meet and was rejected.

Option B

It fulfills but then we will examine it again.

Option C

It fulfills but then we will examine it again.

Option D

This did not meet and was rejected.

Comparison of Option B and Option C

The librarian wanted to purchase as many DVDs as possible. Thus, values of x and y could represent the number of new-release and classic movies bought is .

Keywords: linear programming, the town librarian, a combination of new-release movies on DVD, classic, purchases, budget, as many DVDs as possible

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1