(lots of points, no dumb answers will be reported)
triangle qrp is congruent to triangle yxz. what is the perimeter of triangle yxz?
what is the perimeter of triangle yxz?

6.4 inches

Step-by-step explanation:

As given triangle QRP is congruent to triangle YXZ.

where ∠Q=72°

PR =2.5 inches

∠Z=36°

XY=1.4 inches.

then  QP=YZ,PR=YZ=2.5 , QR=XY=1.4 inches,∠Q=∠Y=72°,

∠P=∠Z=36° and ∠R=∠X= 180°-36°-72°=72°(by angle sum property)

As ∠Y=∠X=72° Hence triangle XYZ is a isosceles triangle .

We know that "Sides opposite to equal angles of a triangle are equal"

⇒YZ=XZ=2.5 inches

Thus the perimeter of triangle YXZ=YX+XZ+ZY=1.4+2.5+2.5=6.4 inches.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

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