Cassidy dropped a ball from a height of 46 yards. after each bounce, the peak height of the ball is half the peak height of the previous height.

how far does the ball travel from the time cassidy drops the ball until it reaches its peak height after the 4th bounce?

120.75 yd

126.5 yd

129.375 yd

132.25 yd

1) Initial fall => 46 yards

2) First bounce = > rising 46/2 yards and falling the same => 23*2 = 46

3) Second bounce => rising   23/2 yards and falling the same => 11.5*2 = 23

 
4) Third bounce => rising 11.5/2 yards and falling the same => 5.75 * 2 = 11.5

5) Fourth bounce => rising 5.75 / 2  yards = 2.875

Sum = 46 + 46 + 23 + 11.5 + 2.875 = 129.375

129.375 yd

It’s going to be d. 4x^2-4x-19’