Given a quadratic function, f(x) = ax 2 + bx + c has a negative leading coefficient and the vertex that has a negative y-coordinate. determine the number of real zeros of the function. 2 real zeros 1 real zero 1 real zero and 1 imaginary zero 2 imaginary zeros

Answer with explanation:

The Given Quadratic function is

→The quadratic function has a negative leading coefficient and the vertex that has a negative y-coordinate.

→The given quadratic function when written , represents a parabola, opening downwards, and can lie either in third Quadrant or fourth Quadrant or in both.

→So, it can be written as

→If Vertex is (c,-k), still the Quadratic function or the  parabola will have no real root, as Imaginary root occur in pairs,you can see the result from the image ,as function does not cross the x axis even once .

Similarly, If Vertex is (-c,-k), still the Quadratic function or a parabola will have no real root, as Imaginary root occur in pairs,you can see the result ,from the image ,as function does not cross the x axis even once .

So, the function has no real root.

Option D: 2 imaginary zeros

the answer is 200

step-by-step explanation:

the way the question is worded, it seems to imply the $264 interest is simple interest, not compound interest.

the simple interest for 2 years is $264; the simple interest for 1 year is $132.

$132 interest on a $600 investment means an interest rate of (132/600)*100 = 22%.

the value of $200 at 22% interest compounded annually for three years is

200%281.22%29%5e3

the amount of interest is that value, minus the original $200.

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm