Alandscaper attaches a guy wire 10 ft up the trunk of a newly planted sapling. he stakes the wire between 20 and 25 feet from the tree. what could be the length of the guy wire if it forms a right triangle with the tree?

The solution would be like this for this specific problem:

Given:

20 feet, 25 feet, 10 ft up

20 * 20 = 400
25 * 25 = 625

Minimum = sqrt(100+400) = 22.36

Maximum = sqrt(100+625) = 26.93

The answer is somewhere between 25 feet.

The solution would be like this for this specific problem:

Given:

20 feet, 25 feet, 10 ft up

20 * 20 = 400

25 * 25 = 625

Minimum = sqrt(100+400) = 22.36

Maximum = sqrt(100+625) = 26.93

The answer is somewhere between 25 feet.

Step-by-step explanation:

just took the test got it right. The exact explanation. good luck!!

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2