How many solutions are possible for a system of equations containing exactly one linear and one quadratic equation? (select all that apply). 0 1 2 3 4

Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C

A linear equation is a straight line. The equation is of the type y = MX + N

The soluction of that system is Ax^2 + Bx + C = MX + N

=> Ax^2 + (B-M)x + (C-N) = 0

That is a quadratic equation.

A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.

So you must select 0, 1 and 2.

You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.

You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.  

X= -5because this is a single step equation so you would just have to divide -16 both sides for x to equal your solution