Given: abcd is a rectangle
diagonals ac and bd intersect at e
prove: triangle aeb is isosceles

Because both diagonals AC and BD are the same length, that means that where they intersect at is the same length(i.e AE and BE). Since those are the same, that means that this triangle should be an isosceles triangle, with at least 2 sides having the same length.

The answer is d. 606 because you have to multiply 30% ( percent) times 2020 (total) to get ur answer.