Elizabeth has two identical number cubes. both cubes have faces numbered 1 through 6. if elizabeth rolls each cube once, what is the probability that the sum of the two numbers on the top faces will be 10.

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

So if Elizabeth rolls each cube once, there is 36 (6 x 6) possible outcomes.

Let E = event of getting a sum of 10.

The number which is a sum 10 will be:

E = [(4,6), (5,5),(6,4)]

P(E) = number of favorable outcomes divided by total number of possible outcomes

        = 3 / 36 or 0.083

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: