Find the sum of the first four terms of the geometric sequence shown below. 4, 4/ 3, 4/9,

It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is



It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.

Multiply the sum by 1/3 and you have



Now subtracting this from gives



That is, all the matching terms will cancel. Now solving for , you
have

31/6= 19/6 19/6 *1/7=19/42