Write the equation of the line that is perpendicular to y = −14x + 2y = -14x + 2 in slope-intercept form and passes through the point (-4, 3)

Hello:
the equation is : y = ax+b
the slope is a : a×(-14) = -1( perpendicular to a line with a slope of -14)

because ;the slope of the line : y = −14x + 2

a = 1/14          y=(1/14)x+b
the line that passes through (-4, 3) : 3 = (1/14)(-4)+b
b = 46/4 
 the equation is :  y  = (1/14)x+46/4

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

what is the answer to this