Marisol grouped the terms and factored the gcf out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. her work is shown. step 1: (6x3 – 22x2) – (9x + 33) step 2: 2x2(3x – 11) – 3(3x + 11)

a. marisol noticed that she does not have a common factor. which accurately describes what marisol should do next?
b. marisol should realize that her work shows that the polynomial is prime.
c. marisol should go back and group the terms in step 1 as (6x3 – 22x2) – (9x –33).
d. marisol should go back and group the terms in step 1 as (6x3 – 22x2) + (9x-33).
d. marisol should refactor the expression in step 2 as 2x2(3x + 11) – 3(3x + 11).

B. Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).

Step-by-step explanation:

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.