. Then the definite integral can be split up at 
so that
![\displaystyle\frac{\mathrm dF}{\mathrm dx}=\frac{\mathrm d}{\mathrm dx}\left[\int_{t=c}^{t=5x}\frac{\mathrm dt}t-\int_{t=c}^{t=2x}\frac{\mathrm dt}t\right]](/tpl/images/0401/6357/6917f.png)
![=\displaystyle\frac1{5x}\dfrac{\mathrm d}{\mathrm dx}[5x]-\frac1{2x}\dfrac{\mathrm d}{\mathrm dx}[2x]](/tpl/images/0401/6357/69053.png)
, we recover 
and find that
is an arbitrary constant.
Calculus !
show that the function is constant over the interval (0, +∞)...
Mathematics, 03.12.2019 21:31 aleiahmartin
Calculus !
show that the function is constant over the interval (0, +∞)
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