Two roots of a 3-degree polynomial equation are 5 and -5. which of the following cannot be the third root of the equation?
there are multiple answers.
5
5i
0
-5
-5i

Option 2 and 5.

Step-by-step explanation:

It is given that two roots of a 3-degree polynomial equation are 5 and -5.

The number of roots is equal to the degree of the polynomial.

Degree of the polynomial is 3 it means the number of roots is 3.

According to the complex conjugate root theorem if a complex number a+ib is a root of polynomial P(x) then its conjugate a-ib is also the root of P(x). It means the number of complex root is always even.

Two given roots are real, so the remaining single root must be a real number.

So, 5i and -5i can not be the third root of the equation.

Therefore, the correct options are 2 and 5.

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

answer: 140

step-by-step explanation:

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