Six red marbles, 4 green marbles and 2 blue marbles are placed in a jar. what is the probability of selecting a green marble and then another green marble given the first marble is not returned to the jar after it is drawn?
a: 2/11
b: 5/22
c: 1/11
d: 5/33

There are 6+4+2=12 total marbpee
P( green marble):4/12=1/3
P( another green marble without replacing): 3/11
As a result, the probability of selecting a green marble and then another green marble given the first marble is not returned to the jar after it is drawn is 1/3×3/11=3/33 or 1/11. Hope it help!