The heights of the trees in a forest are normally distributed, with a mean of 25 meters and a standard deviation of 6 meters. what is the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters? use the portion of the standard normal table given to answer the question.

We are given: 
μ = 25 m
σ = 6 m
x = 37 m

Solving for z score:
z = (x-μ)/σ = (37-25)/6 = 2

Using the standard normal table, the probability of z=2.00 is 0.9772. But since this probability is measured from the left end of the curve, we subtract 1 from it because we are asked for "height greater than or equal to 37 meters", so we take the area of the right side of the curve.

1-0.9772 = 0.0228 = 2.28%