From a standard deck of cards, what is the probability that you choose a red card and then choose a 3 assuming you replaced the first card? a)1/52 b)3/104 c)1/26 d)15/26

A standard deck of cards has 52 cards. Half of the deck has red cards and half has black cards. So the first probability would be 26/52, or 1/2 (simplified, it's half the deck).

Then you put the card back and choose a 3. There are 4 cards with the number 3 in the deck. So it's 4/52.

Then you multiply both the probabilities
26/52 x 4/52 =  = 1/26

Ican't solve. your equation is impossible. you can't have two equal signs.

Idunno because the question doesn’t make sense