Mike and his friends bought cheese wafers for $2 per packet and chocolate wafers for $1 per packet at a carnival. they spent a total of $25 to buy a total of 20 packets of wafers of the two varieties

. part a: write a system of equations that can be solved to find the number of packets of cheese wafers and the number of packets of chocolate wafers that mike and his friends bought at the carnival. define the variables used in the equations.

part b: how many packets of chocolate wafers and cheese wafers did they buy? explain how you got the answer and why you selected a particular method to get the answer.

Lets use x to represent the cheese wafers and y to represent the chocolate wafers.
For part A:
The system of equation would be:
x+y=20 (this equation represents how many were bought)
2x+y=25 (the price. Remember that there is an imaginary 1 in front of the y)
For Part B:
To find how many chocolate wafers were bought, isolate y in the first equation (x+y=20) by bringing y to the other side. You are left with x= 20-y.
Plug the new equation into the second equation (2x+y=25) for x.
Now solve:
Step 1 (Plug in): 2(20-y)+y=25 
Step 2 (Distribute): 40-2y+y=25
Step 3 (Combine like terms): 40-y=25
Step 4 (Subtract 40 from each side of the equation): -y=-15
Step 5 (divide by -y): y=15
Therefore, a total of 15 chocolate wafers were bought. This means that a total of 5 cheese wafers were bought. I got the answer by solving for variables. I selected these particular method, because it is the easiest and most efficient way of solving this problem (in my opinion). Hope I help :). If you have any questions please let me know.

Lets use x to represent the cheese wafers and y to represent the chocolate wafers.
For part A:
The system of equation would be:
x+y=20 (this equation represents how many were bought)
2x+y=25 (the price. Remember that there is an imaginary 1 in front of the y)
For Part B:
To find how many chocolate wafers were bought, isolate y in the first equation (x+y=20) by bringing y to the other side. You are left with x= 20-y.
Plug the new equation into the second equation (2x+y=25) for x.
Now solve:
Step 1 (Plug in): 2(20-y)+y=25 
Step 2 (Distribute): 40-2y+y=25
Step 3 (Combine like terms): 40-y=25
Step 4 (Subtract 40 from each side of the equation): -y=-15
Step 5 (divide by -y): y=15
Therefore, a total of 15 chocolate wafers were bought. This means that a total of 5 cheese wafers were bought. I got the answer by solving for variables. I selected these particular method, because it is the easiest and most efficient way of solving this problem (in my opinion). Hope I help :). If you have any questions please let me know.

Hi! mark me brainliest if i : )y = 0.213x – 352.0    represents this linear model shown in the data table.plug in the values of x into the equation for a double check.let's try 1980.y = 0.213(1980) – 352.0y = 69.74which is closest to the 70.1 whereas other options do not satisfy the condition. 

If i'm correct the answer is $15.97