Arandom two -digit number (10-99)is drawn find each probability
p (32)
p (odd number )
p (a multiple of 5 )

Step-by-step explanation:

Given that two digit numbers are used and one digit is drawn randomly.

Sample space = {10,11,...99}

n(S) = 90

32 is only one number favourable

Hence P(32) = 1/90

Odd numbers are exactly 45.

Hence prob (odd number) = 45/90 = 1/2

Multiples of 5 are 10,15,95

There are exactly 18 numbers.

Hence P(a multiple of 5) = 18/90 =1/5

ok

step-by-step explanation: