An internet password consists of a digit followed by a letter, followed by another digit, assuming the digits are 0-9.how many different passcode are possible?

2,600

Step-by-step explanation:

Given: The total number choices of digits (0-9) for the first and the third place of  internet password= 10

The total number of choices for letters for the middle place of internet password (Number of letters in English alphabet)= 26

Now, the number of different internet passcode are possible is given by :-

Hence, the  number of different internet passcode are possible = 2,600.

idk

step-by-step explanation:

payback

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2